how to convert string to int8 in golang?

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To convert string to int8 in golang, just use ParseInt() method with int8() and pass your string, it will convert string into int8.

As we know the ParseInt() method always return int64 so that’s why we have to use int8() to convert int64 to int8.

Important Points

Difference between int and uint

UInt does not allow for negative numbers.

uint’s and int’s max value

uint8  : 0 to 255 
uint16 : 0 to 65535 
uint32 : 0 to 4294967295 
uint64 : 0 to 18446744073709551615 
int8   : -128 to 127 
int16  : -32768 to 32767 
int32  : -2147483648 to 2147483647 
int64  : -9223372036854775808 to 9223372036854775807

Follow the below tutorial if you are struggling with installing GO in windows.

https://aguidehub.com/blog/how-to-install-golang-in-windows/

Today, I will show you how do I convert string to int8 in golang, as above mentioned I’m going to use ParseInt() way.

The strconv package provide ParseInt() method.

Let’s start our Golang convert string to int8 example

Convert whole string into int8 example

main.go

package main

import (
	"strconv"
	"fmt"
	"reflect"
)

func main() {
	var s string = "10"
  i, err := strconv.ParseInt(s, 10, 64)
  if err != nil {
      panic(err)
  }
  fmt.Println(i, reflect.TypeOf(i))
  
  i8 := int8(i)
  fmt.Println(i8, reflect.TypeOf(i8))
}

In the above example, we have converted string to int8 and printed in golang console. let’s check the output.

Output

10 int64
10 int8

Try it Yourself

I hope it helps you, All the best 👍.