How to convert string to interface in Golang?

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In Go, you can convert a string to an interface by first using the json.Unmarshal() function to convert the string to a map[string]interface{} value, and then using a type assertion to convert the map value to the desired interface type.

Here is an example of how to convert a string to an interface in Go:

package main
import (
  "fmt"
  "encoding/json"
  )

type MyInterface interface {
    SomeMethod()
}

type MyType struct {
    SomeField string
}

func (t *MyType) SomeMethod() {}

func main() {
    jsonData := []byte(`{"SomeField": "Hello World"}`)

    // convert the JSON string to a map
    var m map[string]interface{}
    err := json.Unmarshal(jsonData, &m)
    if err != nil {
        panic(err)
    }

    // convert the map to the MyType type
    var i MyInterface
    i = &MyType{
        SomeField: m["SomeField"].(string),
    }

    fmt.Println(i)
}

In this example, we have an interface type called MyInterface and a type called MyType that implements this interface. We then create a JSON string and use the json.Unmarshal() function to convert it to a map[string]interface{} value.

Next, we use a type assertion to convert the map value to the MyType type, which allows us to create a value of type MyInterface that contains the data from the original JSON string.

You can use this technique to convert any string to an interface in Go.

Output:

&{Hello World}

Try it yourself

All the best 👍

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